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Remove middle digits in C language

How to remove the middle Digits from a number in C. 

The code for Question is given below.
// Program to remove all middle digits of number in c
1. #include<stdio.h>
2. #include<conio.h>
3. void main() {
4.    int n,m;
5.    clrscr();
6.    printf("Enter Any Number:-");
7.    scanf("%d",&n);
8.    m=n%10;
9.    while(n>0) {
10.     n=n/10;
11.     if(n%10!=1) {
12. continue;
13.     }
14.     m=(n%10)*10+m;
15.   }
16.   printf("New Number:- %d",m);
17.   getch();
18.}

Please Find Image Of Code Given Below:-



Find the output given below:-




Let me  explain the code: 

In the given code we first take two variables n and m. we take input in n and then in line 8 we have stored the last digit of the number in m. For example, we have taken the number 12345 a five-digit number and from this, we extract '5' as the last digit number from it. And stored in m.
After that, we make a loop in which condition checks are n greater than 0 if it's true then control goes to the next statement n=n/10; in this statement, n is replaced by a quotient after evaluating that expression. it will iterate until the condition is true.
In the next line if statement checks the condition (n% 10 ! = 1) is true or false. if true then "continue;" statement will be executed rather than the next line will be executed. the "if" condition checks after n dividing by 10 the remainder are not equal to 1. if true then it continues. if not then the next condition will be executed.
In the next statement m stores, the ((n%10)*10 + m) means the remainder left after dividing by 10 and multiplies by 10 and after that added by m previous value.
Hence then you will get an exact result. The middle numbers are removed by IF condition which in a loop. it always continues until it goes to the first place of a number.
I hope you have got your answer.

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